[hellrei15]

Originally Posted by Pozputty

regular octagon means all sides are equal... so *any* side of the octagon = s

if you can visualize it, since you say youve drawn the picture, the hypotenuse of the triangle is equal to one side of the octagon. as ive stated before, any side of the octagon = s. so s = the hypotenuse of the triangle.

so basically what you need to do is find what the hypotenuse of the triangle is with x-long legs. as a hint: if both legs are equal length, x, and that it is also cut from a corner of a square, then you know it is an right isosceles triangle... you can use pythagorean's theorem to quickly find the answer.

Ah... So x = s square root of 2 / 2?

[WuxingBagua]

1 + 1 = uhhhhh.... hmmmmmm..... gimme a sec...... is it 3??? lol

[Duratrix]

Originally Posted by wuxingbagua

1 + 1 = uhhhhh.... hmmmmmm..... gimme a sec...... is it 3??? lol

No silly everybody knows the answer is 4.. tssss how could you make such a mistake?

[miharuendoh]

)))))) Ohh I love math. It`s one of the mains subjects. Rey you are at geometry?
I`m doing integrals... well math analyse and algebra for 4 year.

[BokuWaOtakuJaNai]

Applying the Pythagorean Theorom:

(x^2) + (x^2) = s^2
combine like terms to get
2 * x^2 = s^2
take the square root of both sides to get
(sq. root of 2) * x = s
divide both sides by (sq. root of 2) to get
x = s/(sq. root of 2)

[Pozputty]

Originally Posted by hellrei15

Ah... So x = s square root of 2 / 2?

im assuming you mean x = s*sqrt(2)/2... the other way would be kind of silly to write anyways.

in that case yes.

[BokuWaOtakuJaNai]

can you show your work on that one pozputty? I haven't taken geometry in 15 years, but I thought my math was right.

[Pozputty]

Originally Posted by BokuWaOtakuJaNai

can you show your work on that one pozputty? I haven't taken geometry in 15 years, but I thought my math was right.

1/sqrt(2) = sqrt(2)/2

multiply it by sqrt(2)/sqrt(2) or 1

improper fractions zzzzzzzzzz... i dont really simplify them anymore unless necessary but im guessing in a class like this hellrei's it would be unacceptable to leave it like you have

[BokuWaOtakuJaNai]

oh I see now...I told you it has been awhile. I never even thought to simplify it. What's so bad about leaving a square root in the denominator anyway?

Personally, I think s/sqrt(2) is simpler than [s*sqrt(2)]/2. That's just my opinion though.

[danko]

Originally Posted by wuxingbagua

1 + 1 = uhhhhh.... hmmmmmm..... gimme a sec...... is it 3??? lol

Originally Posted by Duratrix

No silly everybody knows the answer is 4.. tssss how could you make such a mistake?

hehehe... you're both wrong!

1+1=11